A) 2.8 Joule
B) 3.2 Joule
C) 3.8 Joule
D) 4.4 Joule
Correct Answer: D
Solution :
Change in momentum = Force × time \[{{P}_{2}}-{{P}_{1}}=F\times t=0.2\times 10=2\] Þ \[{{P}_{2}}=2+{{P}_{1}}=2+10=12kg\text{-}m/s\] Increase in K.E. = \[\frac{1}{2m}(P_{2}^{2}-P_{1}^{2})\ =\frac{1}{2\times 5}\left[ {{(12)}^{2}}-{{(10)}^{2}} \right]\] \[=\frac{44}{10}=4.4J\]
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