A) \[1.6\times {{10}^{-12}}Joule\]
B) \[1.6\times {{10}^{-19}}Joule\]
C) \[1.5\,\times {{10}^{-10}}Joule\]
D) \[1.5\times {{10}^{-19}}Joule\]
Correct Answer: C
Solution :
1 amu\[=1.66\times {{10}^{-27}}\,kg\] \[E=m{{c}^{2}}=1.66\times {{10}^{-27}}\times {{(3\times {{10}^{8}})}^{2}}=1.5\times {{10}^{-10}}\,J\]
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