A) \[mgh=\frac{1}{2}k{{x}^{2}}\]
B) \[mg(h+x)=\frac{1}{2}k{{x}^{2}}\]
C) \[mgh=\frac{1}{2}k{{(x+h)}^{2}}\]
D) \[mg(h+x)=\frac{1}{2}k{{(x+h)}^{2}}\]
Correct Answer: B
Solution :
Change in gravitational potential energy = Elastic potential energy stored in compressed spring \[\Rightarrow mg(h+x)=\frac{1}{2}k{{x}^{2}}\]
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