A) 48 J
B) 32 J
C) 24 J
D) 288 J
Correct Answer: D
Solution :
As the initial momentum of bomb was zero, therefore after explosion two parts should possess numerically equal momentum i.e. \[{{m}_{A}}{{v}_{A}}={{m}_{B}}{{v}_{B}}\]Þ \[4\times {{v}_{A}}=8\times 6\]Þ \[{{v}_{A}}=12\ m/s\] \ Kinetic energy of other mass A, = \[\frac{1}{2}{{m}_{A}}v_{A}^{2}\] = \[\frac{1}{2}\times 4\times {{(12)}^{2}}\]= 288 J.You need to login to perform this action.
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