A) \[250\sqrt{3}\]N to right
B) 250 N to right
C) \[250\sqrt{3}\]N to left
D) 250 N to left
Correct Answer: C
Solution :
Force = Rate of change of momentum Initial momentum \[{{\vec{P}}_{1}}=mv\sin \theta \ \hat{i}+mv\cos \theta \,\hat{j}\] Final momentum \[{{\vec{P}}_{2}}=-mv\sin \theta \ \hat{i}+mv\cos \theta \,\hat{j}\] \ \[\vec{F}=\frac{\Delta \vec{P}}{\Delta t}=\frac{-2mv\sin \theta }{2\times {{10}^{-3}}}\] Substituting m = 0.1 kg, v = 5 m/s, q = 60° Force on the ball \[\vec{F}=-250\sqrt{3}N\] Negative sign indicates direction of the force
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