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JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Conservation of Energy and Momentum

  • question_answer
    From a stationary tank of mass 125000 pound a small shell of mass 25 pound is fired with a muzzle velocity of 1000 ft/sec. The tank recoils with a velocity of               [NCERT 1973]

    A)                 0.1 ft/sec

    B)                    0.2 ft/sec

    C)                 0.4 ft/sec

    D)                    0.8 ft/sec

    Correct Answer: B

    Solution :

                        According to conservation of momentum Momentum of tank = Momentum of shell 125000 × vtank = 25 × 1000 Þ vtank = 0.2 ft/sec.


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