JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Conservation of Linear Momentum and Impulse

  • question_answer
    A bullet of mass 0.1 kg is fired with a speed of 100 m/sec, the mass of gun is 50 kg. The velocity of recoil is [AFMC 1995; JIPMER 2000; Pb.PMT 2002]

    A)             0.2 m/sec        

    B)             0.1 m/sec

    C)             0.5 m/sec

    D)               0.05 m/sec

    Correct Answer: A

    Solution :

                    According to principle of conservation of linear momentum, \[{{m}_{G}}{{v}_{G}}={{m}_{B}}{{v}_{B}}\]             \[\Rightarrow \] \[{{v}_{G}}=\frac{{{m}_{B}}{{v}_{B}}}{{{m}_{G}}}=\frac{0.1\times {{10}^{2}}}{50}=0.2m/s\]


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