JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Conservation of Linear Momentum and Impulse

  • question_answer
    At a certain instant of time the mass of a rocket going up vertically is 100 kg. If it is ejecting 5 kg of gas per second at a speed of 400 m/s, the acceleration of the rocket would be (taking \[g=10\,m/{{s}^{2}})\]                                [NCERT 1984]

    A)                         \[20\,m/{{s}^{2}}\]            

    B)                           \[10\,m/{{s}^{2}}\]          

    C)                         \[2\,m/{{s}^{2}}\]          

    D)                           \[1\,m/{{s}^{2}}\]

    Correct Answer: B

    Solution :

                    The acceleration of a rocket is given by             \[a=\frac{v}{m}\left( \frac{\Delta m}{\Delta t} \right)-g=\frac{400}{100}\left( \frac{5}{1} \right)-10\]             \[=(20-10)=10\,\,m/{{s}^{2}}\]            


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