Step I: Draw a line segment BC of length 5 cm. |
Step II: Draw an \[\angle XBC={{60}^{o}}\]at point B of line segment BC. |
Step III: Cut off PB = 3.5 cm on the ray BX. |
Step IV: Join PC. |
Step V: Draw\[\bot \]bisector of BC which intersect ray BX at A. Join AC. |
Step VI: ABC is the required triangle. |
A) Step II only
B) Step III only
C) Step II and V
D) Step III and V
Correct Answer: D
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