Step I: Draw a ray BY parallel to AX by making \[\angle ABY\]equal to \[\angle BAX\]. |
Step II: Join \[{{A}_{3}}{{B}_{4}}\]. Suppose it intersects AB at a point P. Then, P is the point dividing AB internally in the ratio \[3:4\]. |
Step III: Draw the line segment AB of length 8 cm. |
Step IV: Mark of three point \[{{A}_{1}},{{A}_{2}},{{A}_{4}}\]on AX and 4 points \[{{B}_{1}},{{B}_{2}},{{B}_{3}},{{B}_{4}}\] on BY such that \[A{{A}_{1}}={{A}_{1}}{{A}_{2}}={{A}_{2}}{{A}_{3}}=B{{B}_{1}}={{B}_{1}}{{B}_{2}}\]\[={{B}_{2}}{{B}_{3}}={{B}_{3}}{{B}_{4}}\]. |
Step V: Draw any ray AX making an acute angle\[~\angle BAX\] with AB. |
A) III, V, I, II. IV
B) III, IV. I, V, II
C) III, I, V, IV, II
D) III, V, I, IV, II
Correct Answer: D
Solution :
Correct sequence of steps is III, V, I, IV, II.You need to login to perform this action.
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