A) \[\underset{x\to 1/2+}{\mathop{\lim }}\,f(x)=2\]
B) \[\underset{x\to 1/2-}{\mathop{\lim }}\,f(x)=2\]
C) \[f(x)\]is continuous at \[x=\frac{1}{2}\]
D) \[f(x)\]is discontinuous at \[x=\frac{1}{2}\]
Correct Answer: D
Solution :
Since \[\underset{x\to 1/2}{\mathop{\lim }}\,\,f(x)\ne f\left( \frac{1}{2} \right)\].You need to login to perform this action.
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