JEE Main & Advanced Mathematics Functions Question Bank Continuity

  • question_answer
    If \[f(x)=\left\{ \begin{matrix}    {{e}^{x}}+ax, & x<0  \\    b{{(x-1)}^{2}}, & x\ge 0  \\ \end{matrix} \right.\] then [DSSE 1986]

    A)            \[\underset{x\to 0+}{\mathop{\lim }}\,f(x)\ne 2\]

    B)            \[\underset{x\to 0-}{\mathop{\lim }}\,f(x)=0\]

    C)            \[f(x)\]is continuous at\[x=0\]

    D)            None of these

    Correct Answer: C

    Solution :

               \[f(0+)=f(0-)=2\] and \[f(0)=2\]            Hence \[f(x)\] is continuous at \[x=0.\]


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