2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Functions

JEE Main & Advanced Mathematics Functions Question Bank Continuity

  • question_answer
    If function \[f(x)=\left\{ \begin{align}   & \frac{{{x}^{2}}-1}{x-1},\,\,\text{when}\,\,x\ne 1 \\  & \,\,\,\,\,\,\,\,\,\,\,\,k,\,\text{when}\,\,x=1 \\ \end{align} \right.\]is continuous at \[x=1\], then the value of k will be            

    A)            ?1

    B)            2

    C)            ?3

    D)            ?2

    Correct Answer: B

    Solution :

               \[\underset{x\to 1}{\mathop{\lim }}\,f(x)=\underset{x\to 1}{\mathop{\lim }}\,x+1=2=k.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner