question_answer

If \[f(x)=\left\{ \begin{align}   & \frac{{{x}^{2}}-1}{x+1},\,\text{when }x\ne -1 \\  & \,\,\,\,\,\,\,\,-2,\,\text{when }x=-1 \\ \end{align} \right.\],then

A)            \[\underset{x\to {{(-1)}^{-}}}{\mathop{\lim }}\,f(x)=-2\]

B)            \[\underset{x\to {{(-1)}^{+}}}{\mathop{\lim }}\,f(x)=-2\]

C)            \[f(x)\]is continuous at \[x=-1\]

D)            All the above are correct