A) 2
B) 3
C) 4
D) ?3
Correct Answer: B
Solution :
We have \[f(x)=2x-1,\]if \[x>2,\] \[f(x)=k,\] If \[x=2\] and \[{{x}^{2}}-1,\] if \[x<2\], function is continuous. \ \[\underset{x\to 2}{\mathop{\lim }}\,f(x)=f(2)\]Þ \[\underset{x\to 2}{\mathop{\lim }}\,(2x-1)=k\Rightarrow k=3\].You need to login to perform this action.
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