A) For all real values of x
B) For \[x=2\]only
C) For all real values of x such that \[x\ne 2\]
D) For all integral values of x only
Correct Answer: A
Solution :
Since \[\underset{x\to 2-}{\mathop{\lim }}\,f(x)=\underset{x\to 2+}{\mathop{\lim }}\,f(x)=f(2)=1\] Also it is continuous for all values of x, less than 2 and greater than 2.
You need to login to perform this action.
You will be redirected in
3 sec
