A) 8
B) ?8
C) 4
D) None of these
Correct Answer: A
Solution :
\[\underset{x\to 0-}{\mathop{\lim }}\,f(x)=\underset{x\to 0-}{\mathop{\lim }}\,\left( \frac{2\,{{\sin }^{2}}2x}{{{(2x)}^{2}}} \right)\,4=8\] \[\underset{x\to 0+}{\mathop{\lim }}\,f(x)=\underset{x\to 0+}{\mathop{\lim }}\,\sqrt{16+\sqrt{x}+4}=8\]. Hence \[a=8\].You need to login to perform this action.
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