A) \[f(x)\]is continuous at \[x=2\]
B) \[f(x)\]is discountinous at \[x=2\]
C) \[\underset{x\to 2}{\mathop{\lim }}\,f(x)=16\]
D) None of these
Correct Answer: B
Solution :
\[\underset{x\to 2}{\mathop{\lim }}\,\,f(x)=\underset{x\to 2}{\mathop{\lim }}\,\,(x+2)\,\,({{x}^{2}}+4)=32,\,\,f(2)=16.\]You need to login to perform this action.
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