A) 8
B) 1
C) ?1
D) None of these
Correct Answer: D
Solution :
If \[x\to 0,\] then the value of \[\sin \frac{1}{x}\] passes through [?1, 1] infinitely many ways, therefore limit of the function does not exist at \[x=0.\] Hence there is no value of k for which the function is continuous at \[x=0.\]You need to login to perform this action.
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