A) \[f(x)\]is discontinuous at \[x=\pi /2\]
B) \[f(x)\]is continuous at \[x=\pi /2\]
C) \[f(x)\]is continuous at \[x=0\]
D) None of these
Correct Answer: A
Solution :
\[\underset{x\to \infty }{\mathop{\lim }}\,\,\frac{4x}{(\sqrt{{{x}^{2}}+8x+3}+\sqrt{{{x}^{2}}+4x+3}}\] and \[f\left( \frac{\pi }{2} \right)=\frac{\pi }{2}.\]You need to login to perform this action.
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