JEE Main & Advanced Mathematics Functions Question Bank Continuity

  • question_answer
    In order that the function\[f(x)={{(x+1)}^{1/x}}\]is continuous at \[x=0\], \[f(0)\]must be defined as              [MNR 1989]

    A)            \[f(0)=0\]

    B)            \[f(0)=e\]

    C)            \[f(0)=1/e\]

    D)            \[f(0)=1\]

    Correct Answer: B

    Solution :

               \[\underset{x\to 0}{\mathop{\lim }}\,\,f(x)=f(0)=\underset{x\to 0}{\mathop{\lim }}\,\,\,{{(1+x)}^{1/x}}=e.\]


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