A) 1
B) ?1
C) 0
D) 2
Correct Answer: C
Solution :
If function \[f(x)\] is continuous at \[x=0,\] then \[f(0)=\underset{x\to 0}{\mathop{\lim }}\,\,f(x)\] Given \[f(0)=k\]; \[f(0)=k=\underset{x\to 0}{\mathop{\lim }}\,\,x\,\left( \sin \frac{1}{x} \right)\] \[f(0)=k=0,\text{ }\left( -1\le \sin \frac{1}{x}\le 1 \right)\]; \[\therefore \,\,\,k=0\]..You need to login to perform this action.
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