JEE Main & Advanced Mathematics Functions Question Bank Continuity

  • question_answer
    For the function \[f(x)\,=\frac{{{\log }_{e}}(1+x)-{{\log }_{e}}(1-x)}{x}\] to be continuous at \[x=0,\] the value of \[f(0),\] should be  [MP PET 2003]

    A)            ?1

    B)            0

    C)            ?2

    D)            2

    Correct Answer: D

    Solution :

               By L-Hospital?s rule \[\underset{x\to 0}{\mathop{\lim }}\,f(x)\] is 2. Therefore, for \[f(x)\] to be continuous, the value of function should be 2.


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