JEE Main & Advanced Mathematics Functions Question Bank Continuity

  • question_answer
    If \[f(x)=\left\{ \begin{align}   & x,\ \ \text{when}0<x<1/2 \\  & 1,\ \ \ \text{when }x=1/2 \\  & 1-x,\text{when}\ \text{1/2}<x<\text{1} \\ \end{align} \right.\], then

    A)            \[\underset{x\to 1/2+}{\mathop{\lim }}\,f(x)=2\]                      

    B)            \[\underset{x\to 1/2-}{\mathop{\lim }}\,f(x)=2\]

    C)            \[f(x)\]is continuous at \[x=\frac{1}{2}\]                                    

    D)            \[f(x)\]is discontinuous at \[x=\frac{1}{2}\]

    Correct Answer: D

    Solution :

               Since \[\underset{x\to 1/2}{\mathop{\lim }}\,\,f(x)\ne f\left( \frac{1}{2} \right)\].


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