question_answer

The graph of \[x+2y=3\]and \[3x-2y=1\]meet the Y-axis at two points having distance

A) \[\frac{8}{3}\] units

B) \[\frac{4}{3}\]units

C) 1 unit

D) 2 units

Correct Answer: D

Solution :

[d] Given lines are \[x+2y=3\]                                (i) and \[3x-2y=1\]                                     (ii) put \[x=0,\]then From Eq. (i) \[y=-\frac{3}{2}\] From Eq. (ii) \[y=-\frac{1}{2}\] Distance between both the points \[=\frac{3}{2}-\left( -\frac{1}{2} \right)=\frac{4}{2}=2\,\text{units}\]