A) \[\frac{8}{3}\] units
B) \[\frac{4}{3}\]units
C) 1 unit
D) 2 units
Correct Answer: D
Solution :
[d] Given lines are \[x+2y=3\] (i) and \[3x-2y=1\] (ii) put \[x=0,\]then From Eq. (i) \[y=-\frac{3}{2}\] From Eq. (ii) \[y=-\frac{1}{2}\] Distance between both the points \[=\frac{3}{2}-\left( -\frac{1}{2} \right)=\frac{4}{2}=2\,\text{units}\] |
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