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SSC Quantitative Aptitude Coordinate Geometry Question Bank Coordinate Geometry and Graphs of Linear Equations (II)

  • question_answer
    The value of k for which the graph of \[(k-1)\,x+1y-2=0\]and \[(2-k)x-3y+1=0\] are parallel is

    A) \[\frac{1}{2}\]

    B) \[-\frac{1}{2}\]

    C)  2

    D) \[-\,2\]

    Correct Answer: A

    Solution :

    [a] Given lines are \[(x-1)+x+y-2=0\]                                 …(i) and \[(2-k)x-3y+1=0\]                            …(ii) Since, the lines (i) and (ii) are parallel. \[\therefore \]      \[\frac{k-1}{2-k}=\frac{1}{-3}\] \[\Rightarrow \]   \[3k-3=-\,2+k\] \[\Rightarrow \]   \[2k=1\] \[\Rightarrow \]   \[k=\frac{1}{2}\]


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