A) \[(20,0)\]
B) \[(-23,0)\]
C) \[\left( \frac{4}{7},0 \right)\]
D) None of these
Correct Answer: C
Solution :
Let \[P(x,0)\] be the point on x-axis which is equidistant from points \[A(-3,4)\] and \[B\,(2,5)\] Distance AP = Distance BP \[\sqrt{{{(x+3)}^{2}}+{{(0-4)}^{2}}}=\sqrt{{{(x-2)}^{2}}+{{(0-5)}^{2}}}\] \[{{(x+3)}^{2}}+16={{(x-2)}^{2}}+25\] \[{{x}^{2}}+9+3x+16={{x}^{2}}+4-4x+25\] \[7x=4\,\,\,\Rightarrow \,\,\,\,x=4/7\] Co-ordinate of \[P(x,0)\] is \[(4/7,0)\]You need to login to perform this action.
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