A) 96
B) 18
C) 50
D) 25
Correct Answer: A
Solution :
Let \[A(-1,6),\,B(-3,-9),\,C(5,-8)\] and \[D(3,9)\]are the vertices of quadrilateral ABCD. Then, Area of quadrilateral ABCD = Area of \[\Delta \,ABC\]Area of \[\Delta \,ACD\] .... (i) Area of (ABCD) \[=59+37=96\]sq. units.You need to login to perform this action.
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