A) \[20.5\]sq. units
B) 41 sq. units
C) 82 sq. units
D) \[61.5\]sq. units
Correct Answer: A
Solution :
Let ABCD be a quadrilateral with vertices \[A(1,1),\,B(3,4),\,C(5,-2)\] and \[D(4,-7)\] Area of quadrilateral ABCD = Area of \[\Delta ABC+\]Area of \[\Delta ADC\] ... (i) Now, area of \[\Delta ABC\] \[=\frac{1}{2}|1(6)+3(-3)+5(-3)|=\frac{1}{2}\times 18=9\,sq.\]units Similarly, area of \[\Delta ADC=\frac{1}{2}|1(-5)+4(-3)+5(8)|\] \[=\frac{1}{2}\times 23=11.5\] sq. units Hence, area of quadrilateral ABCD \[=9+11.5=20.5\] sq. unitsYou need to login to perform this action.
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