A) \[CC{{l}_{4}}\]
B) \[CaC{{l}_{2}}\]
C) \[N{{H}_{4}}Cl\]
D) \[{{H}_{2}}O\]
Correct Answer: C
Solution :
\[N{{H}_{4}}Cl\] has covalent as well as ionic bond. \[\left[ H-\underset{\underset{H}{\mathop{|}}\,}{\overset{\overset{H}{\mathop{|}}\,}{\mathop{N}}}\,\to {{H}^{+}} \right]\,C{{l}^{-}}\]
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