A) 272 pm
B) 136 pm
C) 124 pm
D) 248 pm
Correct Answer: B
Solution :
Middle length of \[{{H}_{2}}=74\,pm\] Length of \[H=\frac{74}{2}=37pm\] Middle length of \[C{{l}_{2}}=198\,pm\] Length of \[Cl\]\[=\frac{198}{2}=99\,pm\] Bond length of HCl = Length of H + Length of Cl = 37 + 99 = 136 pmYou need to login to perform this action.
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