A) Sulphite
B) Sulphide
C) Sulphate
D) Thiosulphate
Correct Answer: B
Solution :
It must be sulphide as \[Pb{{(C{{H}_{3}}COO)}_{2}}\ +\ {{H}_{2}}S\underset{\,\,\,(\text{Black }\,\,\text{ppt}\text{.)}}{\mathop{\to PbS\,\,+}}\,2C{{H}_{3}}COOH\]You need to login to perform this action.
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