A) Tollen's reagent
B) Fehling's solution
C) \[NaOH/{{I}_{2}}/{{H}^{+}}\]
D) \[NaOH/NaI/{{H}^{+}}\]
Correct Answer: C
Solution :
\[\underset{\underset{\,\,\,O}{\mathop{\,\,\,\,|\ |}}\,}{\mathop{{{C}_{2}}{{H}_{5}}-C-C{{H}_{3}}}}\,+{{I}_{2}}+NaOH\to {{C}_{2}}{{H}_{5}}CO_{2}^{-}N{{a}^{+}}+CH{{I}_{3}}\] \[{{C}_{2}}{{H}_{5}}CO_{2}^{-}N{{a}^{+}}\xrightarrow{{{H}^{+}}}{{C}_{2}}{{H}_{5}}COOH+N{{a}^{+}}\]You need to login to perform this action.
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