A) 63%
B) 50%
C) 100%
D) 10%
Correct Answer: A
Solution :
\[2.303\log \frac{{{K}_{2}}}{{{K}_{1}}}=\frac{{{E}_{a}}}{R}\left[ \frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}{{T}_{2}}} \right]\] \[\log \frac{{{K}_{2}}}{{{K}_{1}}}=\frac{9.0\times {{10}^{3}}}{2.303\times 2}\,\,\left[ \frac{308-298}{308\times 298} \right]\] \[\frac{{{K}_{2}}}{{{K}_{1}}}=1.63\,;\,\,{{K}_{2}}=1.63\,{{K}_{1}};\,\frac{1.63{{K}_{1}}-{{K}_{1}}}{{{K}_{1}}}\times 100=63.0%\]
You need to login to perform this action.
You will be redirected in
3 sec
