A) \[1.73\times {{10}^{-4}}M\ {{\min }^{-1}}\]
B) \[3.47\times {{10}^{-5}}M\ {{\min }^{-1}}\]
C) \[3.47\times {{10}^{-4}}M\ {{\min }^{-1}}\]
D) \[1.73\times {{10}^{-5}}M\ {{\min }^{-1}}\]
Correct Answer: C
Solution :
Concentration will fall from 0.1 M concentration to 0.025 M concentration within 2 half lives. \[2\times {{T}_{1/2}}=40\]min \[\therefore \ \ {{T}_{1/2}}=20\] min Rate of reaction = K . c \[=\frac{0.693}{{{T}_{1/2}}}.c\] \[=\frac{0.693}{20}\times {{10}^{-2}}M/\min \] \[=3.47\times {{10}^{-4}}M/{{\min }^{-1}}\].
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