A) \[-\frac{{{E}_{a}}}{R}\]
B) \[+\frac{{{E}_{a}}}{R}\]
C) \[-\frac{{{E}_{a}}}{2.303\,R}\]
D) \[+\frac{{{E}_{a}}}{2.303\,R}\]
Correct Answer: C
Solution :
\[\ln \,\,K=\ln \] \[-\frac{{{E}_{a}}}{RT}\] is Arrhenius equation. Thus plots of ln K vs 1/T will give slope \[=-{{E}_{a}}/RT\] or \[-{{E}_{a}}/2.303R\].
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