A) \[{{O}_{2\,(g)}}+4H_{(aq)}^{+}+4{{e}^{-}}\to 2{{H}_{2}}{{O}_{(l)}}\]
B) \[F{{e}_{(s)}}\to Fe_{(aq)}^{2+}+2{{e}^{-}}\]
C) \[Fe_{(aq)}^{2+}\to Fe_{(aq)}^{3+}+{{e}^{-}}\]
D) \[{{H}_{2(g)}}+2OH_{(aq)}^{-}\to 2{{H}_{2}}{{O}_{(l)}}+2{{e}^{-}}\]
Correct Answer: A
Solution :
At cathode : \[2{{H}^{+}}_{(aq)}+2{{e}^{-}}\to 2H\] \[2H+\frac{1}{2}{{O}_{2}}\to {{H}_{2}}O\] \[\overline{2{{H}^{+}}+\frac{1}{2}{{O}_{2}}+2{{e}^{-}}\to {{H}_{2}}O}\]
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