A) 0.66 moles
B) 0.33 moles
C) 0.66 g
D) 0.33 g
Correct Answer: C
Solution :
The reaction taking place at anode is 2Cl? ® Cl2 + 2e? 1 mole 2 ´ 96500 coulomb Q = i . t = 1 ´ 30 ´ 60 = 1800 coulomb. The amount of chlorine liberated by passing 1800 coulomb of electric charge \[=\frac{1\times 1800\times 71}{2\times 96500}=0.66\,\,g\].You need to login to perform this action.
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