A) \[17.281\times {{10}^{2}}\] years
B) \[172.81\times {{10}^{2}}\] years
C) \[1.7281\times {{10}^{2}}\] years
D) \[1728.1\times {{10}^{2}}\] years
Correct Answer: B
Solution :
\[{{t}_{1/2}}\] of C?14 = 5760 year, \[\lambda =\frac{0.693}{5760},\] Now \[t=\frac{2.303}{\lambda }\log \frac{^{14}C\,\text{original}}{^{14}C\,\text{after}\,\text{time}\,\,t}\] \[=\frac{2.303\times 5760}{0.693}\log \frac{100}{12.5}=\frac{2.303\times 5760\times 0.9030}{0.693}\] = 17281= 172.81 × \[{{10}^{2}}\] years.You need to login to perform this action.
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