A) 4.0 g
B) 8.0 g
C) 12.0 g
D) 16.0 g
Correct Answer: A
Solution :
\[{{N}_{t}}={{N}_{o}}{{\left( \frac{1}{2} \right)}^{n}}\], \[{{N}_{t}}=256\ {{\left( \frac{1}{2} \right)}^{18/3}}\]\[=256\ {{\left( \frac{1}{2} \right)}^{6}}=4\].You need to login to perform this action.
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