A) 92.25
B) 96.87
C) 50
D) 75
Correct Answer: B
Solution :
\[n=\frac{20}{4}=5,\frac{{{N}_{t}}}{{{N}_{o}}}={{\left( \frac{1}{2} \right)}^{5}}=\frac{1}{32},\,\,\therefore \text{decayed}\,\] \[=\left( \text{1--}\frac{\text{1}}{\text{32}} \right)\times 100=\frac{31}{32}\times 100=96.87\].You need to login to perform this action.
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