JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Critical Thinking Questions

  • question_answer A box contains two white balls, three black balls and four red balls. In how many ways can three balls be drawn from the box if at least one black ball is to be included in the  draw [IIT 1986; DCE 1994]

    A) 64

    B) 45

    C) 46

    D) None of these

    Correct Answer: A

    Solution :

    A selection of 3 balls so as to include at least one black ball, can be made in the following 3 mutually exclusive ways (i) 1 black ball and 2 others = \[^{3}{{C}_{1}}\times {{\,}^{6}}{{C}_{2}}=3\times 15=45\] (ii) 2 black balls and one other =\[^{3}{{C}_{2}}\times {{\,}^{6}}{{C}_{1}}=3\times 6=18\] (iii) 3 black balls and no other = \[^{3}{{C}_{3}}=1\] \[\therefore \] Total numbers of ways = 45 + 18 + 1 = 64.

You need to login to perform this action.
You will be redirected in 3 sec spinner