A) \[\frac{1}{2}g{{t}^{2}}\]
B) \[ut-\frac{1}{2}g{{t}^{2}}\]
C) \[(u-gt)t\]
D) \[ut\]
Correct Answer: A
Solution :
The distance covered by the ball during the last t seconds of its upward motion = Distance covered by it in first t seconds of its downward motion From\[h=ut+\frac{1}{2}g\,{{t}^{2}}\] \[h=\frac{1}{2}g\ {{t}^{2}}\] [As u = 0 for it downward motion]
You need to login to perform this action.
You will be redirected in
3 sec
