A) \[Cu+HCl(dil.)\]
B) \[Fe+{{H}_{2}}S{{O}_{4}}\]
C) \[Mg+\text{steam}\]
D) \[Na+\text{alcohol}\]
Correct Answer: A
Solution :
Cu and dil. HCl will not produce \[{{H}_{2}}\].You need to login to perform this action.
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