A) 30
B) 27
C) 8
D) None of these
Correct Answer: B
Solution :
We have, 30 = 2 × 3 × 5. So, 2 can be assigned to either a or b or c i.e. 2 can be assigned in 3 ways. Similarly, each of 3 and 5 can be assigned in 3 ways. Thus, the no. of solutions are 3 × 3 × 3 = 27.You need to login to perform this action.
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