• # question_answer How many different nine-digit numbers can be formed from the digits of the number 223355888 by rearrangement of the digits so that the odd digits occupy even places  [IIT Screening 2000; Karnataka CET 2002] A) 16 B) 36 C) 60 D) 180

There are four even places for the four odd digits 3, 3, 5, 5.   \ The required no. of ways$=\frac{4!}{2!\,2!}\,.\,\frac{5!}{2!\,\,3!}=60$.