JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Critical Thinking Questions

  • question_answer How many different nine-digit numbers can be formed from the digits of the number 223355888 by rearrangement of the digits so that the odd digits occupy even places  [IIT Screening 2000; Karnataka CET 2002]

    A) 16

    B) 36

    C) 60

    D) 180

    Correct Answer: C

    Solution :

    There are four even places for the four odd digits 3, 3, 5, 5.   \ The required no. of ways\[=\frac{4!}{2!\,2!}\,.\,\frac{5!}{2!\,\,3!}=60\].

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