question_answer

A particle starts from rest. Its acceleration versus time (t) is as shown in the figure. The maximum speed of the particle will be              [IIT-JEE (Screening) 2004]          

A)                         110 m/s          

B)                         55 m/s          

C)                         550 m/s            

D)                         660 m/s

Correct Answer: B

Solution :

    The area under acceleration time graph gives change in velocity. As acceleration is zero at the end of 11 sec i.e. \[{{v}_{\max }}=\]Area of \[\Delta OAB\]             \[=\frac{1}{2}\times 11\times 10=55\ m/s\]