JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Critical Thinking Questions

  • question_answer
    When forces \[{{F}_{1}},\,{{F}_{2}},\,{{F}_{3}}\] are acting on a particle of mass m such that \[{{F}_{2}}\] and \[{{F}_{3}}\] are mutually perpendicular, then the particle remains stationary. If the force \[{{F}_{1}}\] is now removed then the acceleration of the particle is [AIEEE 2002]

    A) \[{{F}_{1}}/m\]        

    B) \[{{F}_{2}}{{F}_{3}}/m{{F}_{1}}\]

    C) \[({{F}_{2}}-{{F}_{3}})/m\]

    D)   \[{{F}_{2}}/m\]

    Correct Answer: A

    Solution :

        For equilibrium of system, \[{{F}_{1}}=\sqrt{F_{2}^{2}+F_{3}^{2}}\]          As \[\theta =90{}^\circ \]             In the absence of force \[{{F}_{1}}\], Acceleration\[=\frac{\text{Net force}}{\text{Mass}}\]             \[=\frac{\sqrt{F_{2}^{2}+F_{3}^{2}}}{m}=\frac{{{F}_{1}}}{m}\]


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