A) \[\Delta \overrightarrow{{{P}_{1}}}=-\Delta \overrightarrow{{{P}_{2}}}\]
B) \[\Delta E=-\Delta (PE+KE)=0\]
C) \[\overrightarrow{F}\Delta t=m\Delta \overrightarrow{v}\]
D) \[\Delta \overrightarrow{x}\propto \Delta \overrightarrow{F}\] Where symbols have their usual meaning
Correct Answer: C
Solution :
\[\overrightarrow{F}\Delta t=m\Delta \overrightarrow{v}\]Þ \[F=\frac{m\Delta \overrightarrow{v}}{t}\] By doing so time of change in momentum increases and impulsive force on knees decreases.You need to login to perform this action.
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